Lamar Jackson wins 11th(!) AFC Offensive Player of the Week

Yet another award for Jackson’s Canton-growing career

For the eleventh time in his illustrious career, Baltimore Ravens quarterback Lamar Jackson has won AFC Offensive player of the year.

Jackson’s award follow teammate Derrick Henry who won in Week 4 after bulldozing the Buffalo Bills for 199 yards and two total touchdowns.

This puts Jackson one ahead of Kansas City Chiefs quarterback Patrick Mahomes (10), who had two in 2018 before Jackson became the Ravens’ starter, but two behind Buffalo Bills quarterback Josh Allen (13).

Jackson’s 11 wins ranks second in franchise history for player of the week awards of any position, behind only Justin Tucker, with 12.

Franchise Leaders in Player of the Week awards

1. Justin Tucker – 12
2. Lamar Jackson – 11
3. Ray Lewis – 8
4. Ed Reed – 5 (4 defense, 1 ST)
5. Terrell Suggs – 5
6. Ray Rice – 5
7. Joe Flacco – 3

It’s still a long way to the top if Jackson is to catch others on the list. To break into the Top 40, Jackson will need two more to tie Allen, Daunte Culpepper, Donovan McNabb, Julius Peppers, Bruce Smith and Matt Stover.

Career Leaders in Player of the Week

1. Tom Brady – 40
2. Peyton Manning – 37
3. Drew Brees – 32
4. John Carney – 28
5. Aaron Rodgers – 27